• Sep 18th 2009, 07:21 AM
andyboy179
this is my question:

3 $\frac{1}{5}$ - 1 $\frac{1}{2}$ + 1 $\frac{1}{4}$

im not sure waht to do on it so if you can help please post, thanks
• Sep 18th 2009, 07:34 AM
Quote:

Originally Posted by andyboy179
this is my question:

3 $\frac{1}{5}$ - 1 $\frac{1}{2}$ + 1 $\frac{1}{4}$

im not sure waht to do on it so if you can help please post, thanks

Hi .

Write all these fractions as an improper fraction , then make the denominator common .

$\frac{16}{5}-\frac{3}{2}+\frac{5}{4}$

$=\frac{16\times4}{5\times4}-\frac{3\times10}{2\times10}+\frac{5\times5}{4\time s5}$
• Sep 18th 2009, 07:44 AM
andyboy179
i don't understand the 16 X 4 part, could you go through it a little slower please
• Sep 18th 2009, 07:53 AM
Quote:

Hi .

Write all these fractions as an improper fraction , then make the denominator common .

$\frac{16}{5}-\frac{3}{2}+\frac{5}{4}$

$=\frac{16\times4}{5\times4}-\frac{3\times10}{2\times10}+\frac{5\times5}{4\time s5}$

ok . I am trying to make all the denominator common ie 20

so for $\frac{16}{5}$ , in order to make its denominator 20 ,

i will need to take 5 and multiply by 4 , when i multiply the denominator by 4 , i will need to multiply the numerator by 4 as well
• Sep 18th 2009, 07:55 AM
andyboy179
oh i understand now, thanks i will do it now then get back to you with the answer
• Sep 18th 2009, 07:59 AM
andyboy179
would the answer be, 2 $\frac{19}{20}$
• Sep 18th 2009, 08:09 AM
would the answer be, 2 $\frac{19}{20}$