Hello, can you please slove the logarithm? I don't understand how to open it.

I tried this

But not sure if it is right and don't know what to do next.

EDIT:Oops, wrong topic :x

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- September 17th 2009, 04:50 AMdzeinLogarithm
Hello, can you please slove the logarithm? I don't understand how to open it.

I tried this

But not sure if it is right and don't know what to do next.

EDIT:Oops, wrong topic :x - September 17th 2009, 05:01 AMstapel
- September 17th 2009, 05:03 AMdzein
Nope, I missed some classes due to sickness :/

- September 17th 2009, 05:12 AMstapel
You note that you have not studied logs yet. (I guess you were sick for a couple of weeks?)

The step-by-step instructions won't make any sense until you learn the material you missed, so that's where you'll need to start.

**Logarithms**

**Log Rules**

**Solving Log Equations**

**Solving Exponential Equations**

After you've studied the above, you should be ready to at least get started on this exercise:

Use "The Relationship" to convert the log-base-seven equation to the equivalent exponential form. Subtract the 4 and the x over to the right-hand side. Simplify.

Use "The Relationship" again to covert the log-base-two equation to the equivalent exponential form.

Then you'll need to get fancy. If you get stuck at that stage, please reply showing all of your steps so far, and we'll be glad to help you with the quadratic-form base-two exponential equation. (Wink) - September 17th 2009, 05:42 AMmr fantastic
- September 17th 2009, 12:24 PMKrizalid
- September 17th 2009, 10:23 PMpacman
if f(x) = 2^(3 - x) + 2^x - 9, then the plot agrees with the roots obtained above, x = 0, 3