Given gives the same remainder when divided by
(x-1) and (x-2) . I found that a is -2 and the remainder is 2 .
When g(x) is divided by mx+n , it also gives the same remainder (2) , so find m and n .
I am not really sure about this part ..
Given gives the same remainder when divided by
(x-1) and (x-2) . I found that a is -2 and the remainder is 2 .
When g(x) is divided by mx+n , it also gives the same remainder (2) , so find m and n .
I am not really sure about this part ..
How did you get a= -2? If a= -2, so that , then dividing by x- 1 gives with remainder 2 but dividing by x-2 gives with remainder -8, not 2.
Do you know the "remainder theorem": If polynomial p(x) is divided by x- a, then the remainder is p(a). With a= 1, the remainder is and with a= 2, the remainder is . To have the same remainder when divided by x-1 and x- 2, a must satisfy a+ 4= 8a+ 8.