First, what I always do when doing one of these is make a little column at the side of my paper for reference containing 1xn, 2nx, 3xn, ... up to 9xn where n is the number you're dividing by. (That way you instantly know exactly how many of the n go into what you're currently dividing by.)
You see the first number: you see that 19782 is more than 2 x 9672 so it goes into 19782 twice with something recurring (can't do numbers, me, you'll have to work that one out). So stick a 1 over the 2 of 19782, and subtract that 2 x 9672 from 19782, and write it as a neat subtraction calculation lining up the least significant figure underneath the 2 f the 19782. Then you see you have a number less than 9672. So bring the first digit past the decimal point (which in this case is a zero) to the end of this number, and you have another division sum to do. The answer to that goes after the 2 you've just calculated as the initial partial quotient at the top of your calculation.
And so it goes. Subtract as many of the divisor into the partial dividend as will come out, subtract the difference, bring down the next digit, until you've got as many decimal places as you want.
EDIT: Whoops, sorry, it's 9672 / 19782. The same procedure applies, except this time 19782 does not go into 9672 so put a 0 at the top above the 2 of the 9672 and take the next digit after the d.p. (a zero) and you're now seeing how many times 19782 goes into 96720 tenths. And as I say, use the above procedure.