x2+x-12 . x2^ - 2x-3
x-3 x2^+5x+4
the 2^ is to the second power
Hello michaelmitchellI'm guessing that you mean:
Simplify $\displaystyle \frac{x^2+x-12}{x-3}\cdot\frac{x^2-2x-3}{x^2+5x+4}$
In which case you factorise the quadratic expressions to get:
$\displaystyle \frac{(x-3)(x+4)}{x-3}\cdot\frac{(x-3)(x+1)}{(x+4)(x+1)}$
and then divide out the common factors to get
$\displaystyle \frac{x+4}{1}\cdot\frac{x-3}{x+4}$
and simplify further to get
$\displaystyle x-3$
Grandad