I can't solve this so I hope that you could help me
f(x)=(2x-3)(x-2) What are the values of x which make the function increasing?
If you multiply this out you get $\displaystyle f(x) = 2x^{2} - 7x + 6$. Hopefully you recognize that this quadratic function would graph as a parabola opening upward. It would therefore be increasing everywhere that x is larger than the axis of symmetry (the x coordinate of the vertex).