1. Function question

I can't solve this so I hope that you could help me

f(x)=(2x-3)(x-2) What are the values of x which make the function increasing?

2. You need to find the axis of symmetry. This is halfway between the zeros.

As this function is a positive quadratic all values to the right of this value have the function increasing.

3. Originally Posted by WendyM
$f(x) = (2x-3) (x-2)$ What are the values of x which make the function increasing?
If you multiply this out you get $f(x) = 2x^{2} - 7x + 6$. Hopefully you recognize that this quadratic function would graph as a parabola opening upward. It would therefore be increasing everywhere that x is larger than the axis of symmetry (the x coordinate of the vertex).