I can't solve this so I hope that you could help me (Thinking)

f(x)=(2x-3)(x-2) What are the values of x which make the function increasing?

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- Sep 14th 2009, 10:00 PMWendyMFunction question
I can't solve this so I hope that you could help me (Thinking)

f(x)=(2x-3)(x-2) What are the values of x which make the function increasing? - Sep 14th 2009, 10:13 PMpickslides
You need to find the axis of symmetry. This is halfway between the zeros.

As this function is a positive quadratic all values to the right of this value have the function increasing. - Sep 14th 2009, 10:13 PMpflo
If you multiply this out you get $\displaystyle f(x) = 2x^{2} - 7x + 6$. Hopefully you recognize that this quadratic function would graph as a parabola opening upward. It would therefore be increasing everywhere that x is larger than the axis of symmetry (the x coordinate of the vertex).