# find all real solutions to an equation

• Sep 14th 2009, 08:26 PM
absvalue
find all real solutions to an equation
I'm asked to find all real solutions to the equation...

$\sqrt{2}x^{2} - 1 = 0$

Here is what I've done...

$\sqrt{2}x^{2} = 1$

$x^{2} = \frac{1}{\sqrt{2}}$

$x^{2} = \frac{\sqrt{2}}{2}$

$x = \stackrel{+}{-}\sqrt{\frac{\sqrt{2}}{2}}$

$x = \stackrel{+}{-}\frac{\sqrt[4]{2}}{\sqrt{2}}$

$x = \stackrel{+}{-}\frac{\sqrt[4]{2} \times \sqrt{2}}{2}$

$x = \stackrel{+}{-}\frac{\sqrt[4]{2^{3}}}{2}$

$x = \stackrel{+}{-}\frac{\sqrt[4]{8}}{2}$

• Sep 14th 2009, 08:35 PM
VonNemo19
Quote:

Originally Posted by absvalue
I'm asked to find all real solutions to the equation...

$\sqrt{2}x^{2} - 1 = 0$

Here is what I've done...

$\sqrt{2}x^{2} = 1$

$x^{2} = \frac{1}{\sqrt{2}}$

$x^{2} = \frac{\sqrt{2}}{2}$

$x = \stackrel{+}{-}\sqrt{\frac{\sqrt{2}}{2}}$

$x = \stackrel{+}{-}\frac{\sqrt[4]{2}}{\sqrt{2}}$

$x = \stackrel{+}{-}\frac{\sqrt[4]{2} \times \sqrt{2}}{2}$

$x = \stackrel{+}{-}\frac{\sqrt[4]{2^{3}}}{2}$

$x = \stackrel{+}{-}\frac{\sqrt[4]{8}}{2}$