Been trying to jig this around for a while but i can't seem to get it. I know the basic method for simultaneous equation but this one with x and y as the denominator has thrown me off. Any help would be appreciated.

2x+3y= 10

2/x + 3/y = 5

Printable View

- Sep 14th 2009, 01:04 PMMontydoSimultaneous equation
Been trying to jig this around for a while but i can't seem to get it. I know the basic method for simultaneous equation but this one with x and y as the denominator has thrown me off. Any help would be appreciated.

2x+3y= 10

2/x + 3/y = 5 - Sep 14th 2009, 01:38 PMMatt Westwood
For the 2nd one, multiply top & bottom by xy to simplify it. Then what I'd do would be to substitute for either x or y from the first one, shake it down and then solve the resulting quadratic.

- Sep 15th 2009, 05:07 AMswanz
make x the subject in the seccond formula.

therefore ending up with:x=(4y)/(5y-3)

substitute for x in the first equation

after cancelling everything you end up with the quadratic 3y^2-11y+6=0

factorize it (3y-2)(y-3) =0

y= 3 and (2/3)

substitute in tiher equation to get corresponding x values

(x,y) = (0.5,3) , (4, 2/3)

but i am a little unsure about the fact that the highest power of both x and y in the two equations is 1 so by right to my knowledge they each should have just one solution, we usually eliminate the negative solution but since both solutions are positives in this one, i am unsure. But never the less the above answers work. (are correct)