6x+4 <= x-6 < 4x + 10 My work: 6x+4 <= x-6 < 4x + 10 6x+4+6 <= x < 4x+10+6 6x+10 <= x < 4x+16 Not really sure how to finish this...
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It's much easier if you break it into two separate inequations and then bring the solutions together at the end if necessary: $\displaystyle 6x+10 < x $ $\displaystyle x < 4x+16 $ Can you finish it off now?
Originally Posted by AlphaRock 6x+4 <= x-6 < 4x + 10 My work: 6x+4 <= x-6 < 4x + 10 6x+4+6 <= x < 4x+10+6 6x+10 <= x < 4x+16 Not really sure how to finish this... solve it like this 6x+4<=x-6 5x <= -10 x <= -2 this the first interval x-6 < 4x+10 3x > -16 x > -16/3 now find the intersection of the two intervals (-infinity , -2] and (-16/3 , infinity)
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