can someone plese solve for d, then just write the steps taken,
Thanks.
I got 67mm but its not right, should be about 48mm

360E^3=[(π^2×207E^9×((πd^2)/4))/(1.2/(d/4))^2 ]

sorry cant figure out how to write in eqn properly.

360e^3= [(pie^2*207e^9*((pie*d^2)/4)) / ((1.2/(d/4))^2] does that make sense?

2. Hi psupernak

You can learn to type equation here : http://www.mathhelpforum.com/math-he...-tutorial.html

$\displaystyle 360e^3=\pi^2 207e^9\left(\frac{\frac{\pi d^2}{4}}{\frac{1.2}{\frac{d}{4}}}\right)^2$

Btw, it's pi not pie

3. close, the big brackets and sq. belong to only the 1.2/xxx. so ((1.2/(d/4))^2

4. [IMG]file:///C:/Users/Peter/AppData/Local/Temp/moz-screenshot.jpg[/IMG][IMG]file:///C:/Users/Peter/AppData/Local/Temp/moz-screenshot-1.jpg[/IMG]$\displaystyle 360*10^3= [(pi^2*207*10^9*((pi*d^2)/4))]/[(1.2/(d/4))]^2$

5. tried but still didnt work. Also, along with the brackets in wrong spot, the (1.2/(d/4))^2 is under all of RHS

6. Hi psupernak

$\displaystyle 360e^3=\pi^2 207e^9 \frac{\frac{\pi d^2}{4}}{\left(\frac{1.2}{\frac{d}{4}}\right)^2}$ ?

7. correct!, what am i doing wrong when i try to type it.
Can you please solve and write a quick step by step procedure,
Cheers

8. Hi psupernak

Use \frac{smoething}{something} to write fraction.

How about you write what you've tried then maybe someone can check it for you

9. ill just say what i did, icant igure out the eqn editor.

basically i brought the 4 next to the 1.2, then squared both these. while still above d^2. Then i made the pi^2*207E9*pi*d^2 /4, making, [(pi^3*207E9/4)*.25] * d^2.

Then brought the bottom d^2 up, which made it a d^4. Then had the [(pi^3*207E9/4)*.25] over 23.04 ,which was from (1.2*4)^2

Then had 360E3 * 23.04, then divided LHS by number next to d^4. The 4 rooted answer.

And got 67E-3, which is 67mm.

10. Hi psupernak

From where did you get 0.25 in (pi^3*207 e^9/4)*.25 ?

11. cos it was all that *d/4, which = all that * 1/4 times d.

12. Hi psupernak

There are two 4's. One you use in (pi^3*207 e^9/4) and one you use in "[(pi^3*207E9/4)*.25] over 23.04 ,which was from (1.2*4)^2"

13. its ok, i solved it. Thanks