Alright here goes ((-y^3/2)/(y^-1/3))^3 NOW Sorry about all the brackets, but anyways Ive done all i know how to do to it to simplify it and im pretty sure its just undefined? Who knows :S?
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Originally Posted by Djaevel Alright here goes ((-y^3/2)/(y^-1/3))^3 NOW Sorry about all the brackets, but anyways Ive done all i know how to do to it to simplify it and im pretty sure its just undefined? Who knows :S? I assume this is your expression ... $\displaystyle \left(\frac{-y^{\frac{3}{2}}}{y^{-\frac{1}{3}}}\right)^3 $ first, use the law of exponents for division ... $\displaystyle \frac{-x^a}{x^b} = -x^{a-b}$ ... then cube the result.
But dont y and -y count as different things? I dunno i cant remember all of this
Originally Posted by Djaevel But dont y and -y count as different things? I dunno i cant remember all of this -y is just -1 times y
Ohh gotcha so i just have to make the end result negative, riiigghhtt right its semi coming back to me >< Just started a university math course and i dont remember math 12 at all :S
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