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Math Help - Tell me im not a complete idiot :P

  1. #1
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    Tell me im not a complete idiot :P

    Alright here goes

    ((-y^3/2)/(y^-1/3))^3

    NOW

    Sorry about all the brackets, but anyways

    Ive done all i know how to do to it to simplify it and im pretty sure its just undefined? Who knows :S?
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  2. #2
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    Quote Originally Posted by Djaevel View Post
    Alright here goes

    ((-y^3/2)/(y^-1/3))^3

    NOW

    Sorry about all the brackets, but anyways

    Ive done all i know how to do to it to simplify it and im pretty sure its just undefined? Who knows :S?
    I assume this is your expression ...

    \left(\frac{-y^{\frac{3}{2}}}{y^{-\frac{1}{3}}}\right)^3<br />

    first, use the law of exponents for division ... \frac{-x^a}{x^b} = -x^{a-b}

    ... then cube the result.
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  3. #3
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    But dont y and -y count as different things? I dunno i cant remember all of this
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  4. #4
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    Quote Originally Posted by Djaevel View Post
    But dont y and -y count as different things? I dunno i cant remember all of this
    -y is just -1 times y
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  5. #5
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    Ohh gotcha so i just have to make the end result negative, riiigghhtt right its semi coming back to me >< Just started a university math course and i dont remember math 12 at all :S
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