Tell me im not a complete idiot :P

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September 13th 2009, 03:00 PM
Djaevel

Tell me im not a complete idiot :P

Alright here goes

((-y^3/2)/(y^-1/3))^3

NOW

Sorry about all the brackets, but anyways

Ive done all i know how to do to it to simplify it and im pretty sure its just undefined? Who knows :S?
September 13th 2009, 03:28 PM
skeeter

Quote:

Originally Posted by Djaevel

Alright here goes

((-y^3/2)/(y^-1/3))^3

NOW

Sorry about all the brackets, but anyways

Ive done all i know how to do to it to simplify it and im pretty sure its just undefined? Who knows :S?

I assume this is your expression ...

$\left(\frac{-y^{\frac{3}{2}}}{y^{-\frac{1}{3}}}\right)^3<br />$

first, use the law of exponents for division ... $\frac{-x^a}{x^b} = -x^{a-b}$

... then cube the result.
September 13th 2009, 03:34 PM
Djaevel

But dont y and -y count as different things? I dunno i cant remember all of this
September 13th 2009, 03:43 PM
skeeter

Quote:

Originally Posted by Djaevel

But dont y and -y count as different things? I dunno i cant remember all of this

-y is just -1 times y
September 13th 2009, 03:56 PM
Djaevel

Ohh gotcha so i just have to make the end result negative, riiigghhtt right its semi coming back to me >< Just started a university math course and i dont remember math 12 at all :( :S

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