# Tell me im not a complete idiot :P

• Sep 13th 2009, 03:00 PM
Djaevel
Tell me im not a complete idiot :P
Alright here goes

((-y^3/2)/(y^-1/3))^3

NOW

Sorry about all the brackets, but anyways

Ive done all i know how to do to it to simplify it and im pretty sure its just undefined? Who knows :S?
• Sep 13th 2009, 03:28 PM
skeeter
Quote:

Originally Posted by Djaevel
Alright here goes

((-y^3/2)/(y^-1/3))^3

NOW

Sorry about all the brackets, but anyways

Ive done all i know how to do to it to simplify it and im pretty sure its just undefined? Who knows :S?

I assume this is your expression ...

$\displaystyle \left(\frac{-y^{\frac{3}{2}}}{y^{-\frac{1}{3}}}\right)^3$

first, use the law of exponents for division ... $\displaystyle \frac{-x^a}{x^b} = -x^{a-b}$

... then cube the result.
• Sep 13th 2009, 03:34 PM
Djaevel
But dont y and -y count as different things? I dunno i cant remember all of this
• Sep 13th 2009, 03:43 PM
skeeter
Quote:

Originally Posted by Djaevel
But dont y and -y count as different things? I dunno i cant remember all of this

-y is just -1 times y
• Sep 13th 2009, 03:56 PM
Djaevel
Ohh gotcha so i just have to make the end result negative, riiigghhtt right its semi coming back to me >< Just started a university math course and i dont remember math 12 at all :( :S