Thank you, now off to the second problem. lol
I appreciate your time and help.
Cross multiplying is when you multiply by 1 but change 1 to the form a/a where a is the bottom of the other fraction:
$\displaystyle
\frac{197}{22} + \frac{3}{4} - \frac{5}{12}
$
First multiply $\displaystyle \frac{3}{4}$ by $\displaystyle \frac{3}{3}$ to give a denominator of 12. This will make it easier to multiply later
$\displaystyle \frac{3}{4} \times \frac{3}{3} = \frac{9}{12}$
As the last two terms have an equal denominator we can combine and simplify
$\displaystyle
\frac{197}{22} + \frac{9-5}{12} = \frac{4}{12} = \frac{197}{22} + \frac{1}{3}
$
Now we multiply each by the other's denominator to give them the same denominator
$\displaystyle \frac{197}{22} \times \frac{3}{3} = \frac{197 \times 3}{3 \times 22}$
$\displaystyle \frac{1}{3} \times \frac{22}{22} = \frac{22}{3 \times 22}$
Now they have the same denominator we can combine
$\displaystyle \frac{591+22}{66}$
which is the answer