How would i do this work out?

**Math Noob** · Sep 13th 2009, 09:27 AM

Thank you, now off to the second problem. lol

I appreciate your time and help.

**e^(i*pi)** · Sep 13th 2009, 10:46 AM

Cross multiplying is when you multiply by 1 but change 1 to the form a/a where a is the bottom of the other fraction:

$<br /> \frac{197}{22} + \frac{3}{4} - \frac{5}{12}<br />$

First multiply $\frac{3}{4}$ by $\frac{3}{3}$ to give a denominator of 12. This will make it easier to multiply later

$\frac{3}{4} \times \frac{3}{3} = \frac{9}{12}$

As the last two terms have an equal denominator we can combine and simplify

$<br /> \frac{197}{22} + \frac{9-5}{12} = \frac{4}{12} = \frac{197}{22} + \frac{1}{3}<br />$

Now we multiply each by the other's denominator to give them the same denominator

$\frac{197}{22} \times \frac{3}{3} = \frac{197 \times 3}{3 \times 22}$

$\frac{1}{3} \times \frac{22}{22} = \frac{22}{3 \times 22}$

Now they have the same denominator we can combine

$\frac{591+22}{66}$

which is the answer

**Math Noob** · Sep 13th 2009, 01:31 PM

I still don't get it. is there a step by step tut i can use or video of some sort? I searched and google but did not come across problems as similar as mine i greatly appreciate it.

What term would be used when doing such problems?

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