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Math Help - How would i do this work out?

  1. #16
    Junior Member
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    Thank you, now off to the second problem. lol

    I appreciate your time and help.
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  2. #17
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    e^(i*pi)'s Avatar
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    Cross multiplying is when you multiply by 1 but change 1 to the form a/a where a is the bottom of the other fraction:

    <br />
\frac{197}{22} + \frac{3}{4} - \frac{5}{12}<br />

    First multiply \frac{3}{4} by \frac{3}{3} to give a denominator of 12. This will make it easier to multiply later

    \frac{3}{4} \times \frac{3}{3} = \frac{9}{12}

    As the last two terms have an equal denominator we can combine and simplify

    <br />
\frac{197}{22} + \frac{9-5}{12} = \frac{4}{12} = \frac{197}{22} + \frac{1}{3}<br />

    Now we multiply each by the other's denominator to give them the same denominator

    \frac{197}{22} \times \frac{3}{3} = \frac{197 \times 3}{3 \times 22}

    \frac{1}{3} \times \frac{22}{22} = \frac{22}{3 \times 22}

    Now they have the same denominator we can combine

    \frac{591+22}{66}

    which is the answer
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  3. #18
    Junior Member
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    I still don't get it. is there a step by step tut i can use or video of some sort? I searched and google but did not come across problems as similar as mine i greatly appreciate it.

    What term would be used when doing such problems?
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