How would you solve for x? For some reason I just can't figure them out... I greatly appreciate anyone who could help me
#1) y= √x
y = x^2
#2) y=e^-x
y=e^x
#3) y=4-x^2
y=1-x^2
#4)
y=e^x
y=ex
#5) y=x^3-3x+1
x+y
Hi
(1) $\displaystyle y^2=x$ ---1 (square both sides)
$\displaystyle y=x^2 $---2
sub 2 into 1
$\displaystyle (x^2)^2=x $
$\displaystyle
x^4=x
$
$\displaystyle x^4-x=0$ .... continue here
(2) $\displaystyle y^x=e$ --1
$\displaystyle y=e^x$ ---2
sub 2 into 1
$\displaystyle (e^x)^x=e $
$\displaystyle e^{2x}=e $
continue here
Can you try the rest ?
1) Factor. Apply the difference-of-cubes formula to x^3 - 1. Solve the two linear factors.
2) To learn how to solve exponential equations, try here.