?x^4y^5 times 3(three is a radicand)?x^2y^5 times 5(five being another radicand)?x^5

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- Sep 12th 2009, 04:43 PMmd56Let's pretend ? is a radical
?x^4y^5 times 3(three is a radicand)?x^2y^5 times 5(five being another radicand)?x^5

- Sep 12th 2009, 06:45 PMmr fantastic
Please learn some basic latex so that people don't have to waste time deciphering what is posted: http://www.mathhelpforum.com/math-he...-tutorial.html

I assume the expression is $\displaystyle \sqrt{x^4 y^5} \times \sqrt[3]{x^2 y^5} \times \sqrt[5]{x^5}$.

The latex code for this is [tex]\sqrt{x^4 y^5} \times \sqrt[3]{x^2 y^5} \times \sqrt[5]{x^5}[/tex] - Sep 12th 2009, 06:47 PMHallsofIvy
Now, assuming that the formula is what mr. fantastic said, what is your question?

- Sep 12th 2009, 07:23 PM11rdc11
simplify first

$\displaystyle (\sqrt{x^4y^5})(\sqrt[3]{x^2y^5})(x)$

then change everything to a common power

$\displaystyle \sqrt[6]{(x^4y^5)^3(x^2y^5)^2(x)^6} $

can you finish up?