Let's pretend ? is a radical

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• Sep 12th 2009, 04:43 PM
md56
Let's pretend ? is a radical
?x^4y^5 times 3(three is a radicand)?x^2y^5 times 5(five being another radicand)?x^5
• Sep 12th 2009, 06:45 PM
mr fantastic
Quote:

Originally Posted by md56
?x^4y^5 times 3(three is a radicand)?x^2y^5 times 5(five being another radicand)?x^5

Please learn some basic latex so that people don't have to waste time deciphering what is posted: http://www.mathhelpforum.com/math-he...-tutorial.html

I assume the expression is $\displaystyle \sqrt{x^4 y^5} \times \sqrt[3]{x^2 y^5} \times \sqrt[5]{x^5}$.

The latex code for this is $$\sqrt{x^4 y^5} \times \sqrt[3]{x^2 y^5} \times \sqrt[5]{x^5}$$
• Sep 12th 2009, 06:47 PM
HallsofIvy
Now, assuming that the formula is what mr. fantastic said, what is your question?
• Sep 12th 2009, 07:23 PM
11rdc11
simplify first

$\displaystyle (\sqrt{x^4y^5})(\sqrt[3]{x^2y^5})(x)$

then change everything to a common power

$\displaystyle \sqrt[6]{(x^4y^5)^3(x^2y^5)^2(x)^6}$

can you finish up?