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Math Help - Algebra help

  1. #1
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    Algebra help

    x+2y=6, 2x+y=9


    how would I solve that?
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  2. #2
    No one in Particular VonNemo19's Avatar
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    Quote Originally Posted by Rakaa View Post
    x+2y=6, 2x+y=9


    how would I solve that?



    Then solve the system, you must!

    Do you know at all where to begin?
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  3. #3
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    Quote Originally Posted by VonNemo19 View Post
    Then solve the system, you must!

    Do you know at all where to begin?
    Hold on trying to format it correctly


    Y= - 1/2 x - 3

    Y= 2/1 x+3 (This is where im confused
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  4. #4
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    Quote Originally Posted by Rakaa View Post
    Hold on trying to format it correctly


    Y= - 1/2 x - 3

    Y= 2/1 x+3 (This is where im confused
    okay thats the best I could format it
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  5. #5
    No one in Particular VonNemo19's Avatar
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    Quote Originally Posted by Rakaa View Post
    Hold on trying to format it correctly


    Y= - 1/2 x - 3

    Y= 2/1 x+3 (This is where im confused
    OK that's good, you're trying to soleve for a variable. But...

    2x+y=9
    y=9-2x

    Now, you've gotta put this somewhere. Where do you think that we should put 9-2x ?
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  6. #6
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    Quote Originally Posted by vonnemo19 View Post
    ok that's good, you're trying to soleve for a variable. But...

    2x+y=9
    y=9-2x

    now, you've gotta put this somewhere. Where do you think that we should put 9-2x ?
    - 2/9 ?
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  7. #7
    No one in Particular VonNemo19's Avatar
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    Quote Originally Posted by Rakaa View Post
    - 2/9 ?
    No, we must sub this back into the other equation and solve for x.

    Like so...
    x+2\overbrace{(9-2x)}^y=6
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