x+2y=6, 2x+y=9 how would I solve that?
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Originally Posted by Rakaa x+2y=6, 2x+y=9 how would I solve that? Then solve the system, you must! Do you know at all where to begin?
Originally Posted by VonNemo19 Then solve the system, you must! Do you know at all where to begin? Hold on trying to format it correctly Y= - 1/2 x - 3 Y= 2/1 x+3 (This is where im confused
Originally Posted by Rakaa Hold on trying to format it correctly Y= - 1/2 x - 3 Y= 2/1 x+3 (This is where im confused okay thats the best I could format it
Originally Posted by Rakaa Hold on trying to format it correctly Y= - 1/2 x - 3 Y= 2/1 x+3 (This is where im confused OK that's good, you're trying to soleve for a variable. But... $\displaystyle 2x+y=9$ $\displaystyle y=9-2x$ Now, you've gotta put this somewhere. Where do you think that we should put $\displaystyle 9-2x$ ?
Originally Posted by vonnemo19 ok that's good, you're trying to soleve for a variable. But... $\displaystyle 2x+y=9$ $\displaystyle y=9-2x$ now, you've gotta put this somewhere. Where do you think that we should put $\displaystyle 9-2x$ ? - 2/9 ?
Originally Posted by Rakaa - 2/9 ? No, we must sub this back into the other equation and solve for x. Like so... $\displaystyle x+2\overbrace{(9-2x)}^y=6$
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