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Thread: remainder

  1. September 12th 2009, 08:01 AM #1
    kasia.ogor
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    remainder

    the remainder obtained when 2x^3 + ax^2 - 6x + 1 is divided by (x+2) is twice the remainder obtained when the same expression is divided by (x-1). Find the value of a.
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  2. September 12th 2009, 10:11 AM #2
    red_dog
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    Let P(x)=2x^3+ax^2-6x+1

    The remainder when dividing by x+2 is P(-2)

    The remainder when dividing by x-1 is P(1)

    Then we have P(-2)=2P(1)

    Now find a.
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