Since Bradon is defined in terms of Clement and Sandy is defined in terms of Bradon, pick a variable for Clement, andwork from there.

start:

Clement: c

Bradon: 1.2c

Sandy: 1.5(1.2c) = 1.8c

changes:

Sandy: 1.8c - 350

Bradon: 1.2c - 400 + s

Clement: c + 400 + (350 - s) = c + 750 - s

end:

(1.8c - 350) : (1.2c - 400 + s) : (c + 750 - s) = 1 : 1 : 3

Then:

1.8c - 350 = 1.2c - 400 + s

...and:

3(1.8c - 350) = c + 750 - s

Solve the resulting system of equations.