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Math Help - Help simplifying

  1. #1
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    Help simplifying

    I can't seem to simplify this correctly


     20(5-\frac{t}{4})-2(5-\frac{t}{4})^2 + t(5-\frac{t}{4})
    Can someone show me step by step how i break this down?
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  2. #2
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    Quote Originally Posted by el123 View Post
    I can't seem to simplify this correctly


     20(5-\frac{t}{4})-2(5-\frac{t}{4})^2 + t(5-\frac{t}{4})
    Can someone show me step by step how i break this down?
    Hi

    You can see that  5-\frac{t}{4} can be factored

     20\left(5-\frac{t}{4}\right)-2\left(5-\frac{t}{4}\right)^2 + t\left(5-\frac{t}{4}\right) = \left(5-\frac{t}{4}\right)\left(20 - 2 \left(5-\frac{t}{4}\right) + t\right)

     20\left(5-\frac{t}{4}\right)-2\left(5-\frac{t}{4}\right)^2 + t\left(5-\frac{t}{4}\right) = \left(5-\frac{t}{4}\right)\left(20-10+\frac{t}{2}+t\right)

     20\left(5-\frac{t}{4}\right)-2\left(5-\frac{t}{4}\right)^2 + t\left(5-\frac{t}{4}\right) = \left(5-\frac{t}{4}\right)\left(10+\frac{3t}{2}\right)
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  3. #3
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    ok i orginally wrote it wrong but i get what t6 do , but now im stuck on this part

     -2(5-\frac{t}{4})^2

    I keep getting

     -2(25 -10t+\frac{t^2}{4}

    which gives
     -50 + 20t+\frac{t^2}{8}


    But it doesn't fit into what my answer should be, i think i expanded that wrong.
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  4. #4
    Super Member Matt Westwood's Avatar
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    Quote Originally Posted by el123 View Post
    ok i orginally wrote it wrong but i get what t6 do , but now im stuck on this part

     -2(5-\frac{t}{4})^2

    I keep getting

     -2(25 -10t+\frac{t^2}{4}

    which gives
     -50 + 20t+\frac{t^2}{8}


    But it doesn't fit into what my answer should be, i think i expanded that wrong.
    Like this:

     -2\left({5-\frac{t}{4}}\right)^2

    = -2 \left({5^2 - 2 \times 5 \left({\frac{t}{4}}\right) + \left({\frac{t}{4}}\right)^2}\right)

    = -2 \left({5^2 - \frac {5t} 2 + \frac{t^2}{16}}\right)
    Last edited by Matt Westwood; September 12th 2009 at 05:53 AM. Reason: hadn't finished
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