(3x+3)/(x-3)=7 Foiled the left side to get 3x-9x+3x-9=7 multiplied the right side to get 3x-9x+3x-9=7x-21 solve -3x-9=7x-21 -3x=7x-12 -10x=-12 x=1.2
Follow Math Help Forum on Facebook and Google+
Originally Posted by dtownangel (3x+3)/(x-3)=7 Foiled the left side to get 3x-9x+3x-9=7 multiplied the right side to get 3x-9x+3x-9=7x-21 solve -3x-9=7x-21 -3x=7x-12 -10x=-12 x=1.2 $\displaystyle \frac{3x+3}{x-3} = 7$ $\displaystyle 3x+3 = 7(x-3)$ $\displaystyle 3x+3 = 7x-21$ $\displaystyle 24=4x$ $\displaystyle x=6$
so where did i go wrong?
ah i just went a more complicated route. probably leading to a mistake
Well, the first step looks a little strange... How did you get $\displaystyle 3x-9x+3x-9=7$ from $\displaystyle \frac{(3x+3)}{(x-3)}=7$?
Originally Posted by dtownangel ah i just went a more complicated route. probably leading to a mistake You can't foil the left side
yeah i got some ill-advice from a friend.
View Tag Cloud