Solve for x 2x/(x-3)=4+(6/(x-3) 2x=4+6 2x=10 x=5 But if I put 5 in for x in the equation it doesnt work. Where am I going wrong?
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You cannot cancel the (x-3)'s as you did. Take this case which is similar: 20/4 = 2 + 12/4 You can plainly see that 20 is not equal 2 + 12, right?
yes
You are getting confused there is no solution for this problem.
20/4 = 2 + 12/4 If we change the 2 to 8/4, then: 20/4 = 8/4 + 12/4 20 = 8 + 12 Clear? Work your problem the same way.
alright! thanks.
Originally Posted by 11rdc11 You are getting confused there is no solution for this problem. True; but I think his equation: 2x/(x-3)=4+(6/(x-3) should be: 2x/(x-3) = 4 + 6x/(x-3)
well its 6 over x-3
Originally Posted by dtownangel well its 6 over x-3 Like this? $\displaystyle \frac{2x}{x-3} = 4 + \frac{6}{x-3}$
yeah does x=-3
Last edited by mr fantastic; Sep 11th 2009 at 07:50 PM. Reason: Merged posts
Originally Posted by dtownangel yeah K then the problem has no solution. When you work it out you end up with x= 3 which can't be because you would be dividing by zero which is not allowed
No; you should get x = 3. Which means "no solution", since x - 3 = 0; division by 0 is illegal.
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