Solve for x

2x/(x-3)=4+(6/(x-3)

2x=4+6

2x=10

x=5

But if I put 5 in for x in the equation it doesnt work.

Where am I going wrong?

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- September 11th 2009, 05:43 PMdtownangelsolving for x.
Solve for x

2x/(x-3)=4+(6/(x-3)

2x=4+6

2x=10

x=5

But if I put 5 in for x in the equation it doesnt work.

Where am I going wrong? - September 11th 2009, 05:59 PMWilmer
You cannot cancel the (x-3)'s as you did.

Take this case which is similar:

20/4 = 2 + 12/4

You can plainly see that 20 is not equal 2 + 12, right? - September 11th 2009, 06:09 PMdtownangel
yes

- September 11th 2009, 06:16 PM11rdc11
You are getting confused there is no solution for this problem.

- September 11th 2009, 06:18 PMWilmer
20/4 = 2 + 12/4

If we change the 2 to 8/4, then:

20/4 = 8/4 + 12/4

20 = 8 + 12

Clear?

Work your problem the same way. - September 11th 2009, 06:37 PMdtownangel
alright! thanks.

- September 11th 2009, 06:57 PMWilmer
- September 11th 2009, 06:59 PMdtownangel
well its 6 over x-3

- September 11th 2009, 07:03 PM11rdc11
- September 11th 2009, 07:14 PMdtownangel
yeah

does x=-3 - September 11th 2009, 07:17 PM11rdc11
- September 11th 2009, 07:20 PMWilmer
No; you should get x = 3.

Which means "no solution", since x - 3 = 0; division by 0 is illegal.