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Thread: solving for x using logs

  1. September 11th 2009, 03:45 PM #1
    christiangirl
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    solving for x using logs

    Hey, it has been a while since I have used logs, so I am having trouble solving this math problem:
    20 = 3log(x+1)
    Thanks!
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  2. September 11th 2009, 03:50 PM #2
    skeeter
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    Quote Originally Posted by christiangirl View Post
    Hey, it has been a while since I have used logs, so I am having trouble solving this math problem:
    20 = 3log(x+1)
    Thanks!
    assuming log is base 10 ...

    20 = 3\log(x+1)

    20 = \log(x+1)^3

    (x+1)^3 = 10^{20}

    x+1 = 10^{\frac{20}{3}}

    x = 10^{\frac{20}{3}} - 1<br />
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  3. September 11th 2009, 03:51 PM #3
    christiangirl
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    oh sorry it is base 2...
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  4. September 11th 2009, 04:08 PM #4
    Krizalid
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    no matter, the procedure is given above, apply it anyway.
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  5. September 11th 2009, 04:10 PM #5
    christiangirl
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    is it any different if it is base 2?
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  6. September 11th 2009, 04:11 PM #6
    christiangirl
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    oh I see I use 2 instead of 10.
    Thanks!
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