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Math Help - solving for x using logs

  1. #1
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    solving for x using logs

    Hey, it has been a while since I have used logs, so I am having trouble solving this math problem:
    20 = 3log(x+1)
    Thanks!
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  2. #2
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    Quote Originally Posted by christiangirl View Post
    Hey, it has been a while since I have used logs, so I am having trouble solving this math problem:
    20 = 3log(x+1)
    Thanks!
    assuming log is base 10 ...

    20 = 3\log(x+1)

    20 = \log(x+1)^3

    (x+1)^3 = 10^{20}

    x+1 = 10^{\frac{20}{3}}

    x = 10^{\frac{20}{3}} - 1<br />
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  3. #3
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    oh sorry it is base 2...
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  4. #4
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    no matter, the procedure is given above, apply it anyway.
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  5. #5
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    is it any different if it is base 2?
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  6. #6
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    oh I see I use 2 instead of 10.
    Thanks!
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