# Math Help - solving for x using logs

1. ## solving for x using logs

Hey, it has been a while since I have used logs, so I am having trouble solving this math problem:
20 = 3log(x+1)
Thanks!

2. Originally Posted by christiangirl
Hey, it has been a while since I have used logs, so I am having trouble solving this math problem:
20 = 3log(x+1)
Thanks!
assuming log is base 10 ...

$20 = 3\log(x+1)$

$20 = \log(x+1)^3$

$(x+1)^3 = 10^{20}$

$x+1 = 10^{\frac{20}{3}}$

$x = 10^{\frac{20}{3}} - 1
$

3. oh sorry it is base 2...

4. no matter, the procedure is given above, apply it anyway.

5. is it any different if it is base 2?

6. oh I see I use 2 instead of 10.
Thanks!