• Sep 10th 2009, 02:56 PM
Jeffrey6264
Hi, I really need help at umm prime factorization....uhh i think its like using exponents, so yeah... 36 , 81 , 65 , 19 , 24 , 18 , 40 , 75 , 27 , 32 , 49 , 25 , 42 , 104 , 55 , and 77
• Sep 10th 2009, 03:12 PM
pickslides
Here's an example, I will keep reducing my factors until they are prime. Once this is done I put them into index form

$\displaystyle 36 = 6\times 6 = (3\times 2)\times (3 \times 2) = 3^2\times 2^2$

Index form works as follows

$\displaystyle a\times a = a^2$

$\displaystyle a\times a \times a = a^3$

$\displaystyle a\times a \times a \times a= a^4$

and so on...
• Sep 10th 2009, 03:17 PM
Jeffrey6264
Quote:

Originally Posted by pickslides
Here's an example, I will keep reducing my factors until they are prime. Once this is done I put them into index form

$\displaystyle 36 = 6\times 6 = (3\times 2)\times (3 \times 2) = 3^2\times 2^2$

Index form works as follows

$\displaystyle a\times a = a^2$

$\displaystyle a\times a \times a = a^3$

$\displaystyle a\times a \times a \times a= a^4$

and so on...

im really stupid....i dont really get what you mean...i just moved in USA 3 years....P.S. ME AZN (Asian)
(Crying)
• Sep 10th 2009, 03:35 PM
pickslides
which bit could you follow? do you know the multiplication tables?
• Sep 10th 2009, 03:38 PM
Jeffrey6264
Quote:

Originally Posted by pickslides
which bit could you follow? do you know the multiplication tables?

yes....I know that...... i need help with prime factorization using exponents
• Sep 10th 2009, 03:52 PM
pickslides
My first post in this thread is doing exactly what you are after, study it.

Here is another example

$\displaystyle 81 = 9\times 9 = (3\times 3) \times (3\times 3) = 3^4$

I made 81 into factors of 9, then the 9s into factors of 3.

As I had $\displaystyle (3\times 3) \times (3\times 3)$ I could say that was $\displaystyle 3^4$