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Thread: What is x in 12x^2 - (4/squarerootx) = 0?

  1. September 10th 2009, 01:02 PM #1
    marie7
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    What is x in 12x^2 - (4/squarerootx) = 0?

    What is x in 12x^2 - (4/squarerootx) = 0?
    Last edited by mr fantastic; September 11th 2009 at 05:27 AM. Reason: Copied question from post title into main body of post
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  2. September 10th 2009, 01:21 PM #2
    e^(i*pi)
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    Quote Originally Posted by marie7 View Post
    What is x in 12x^2 - (4/squarerootx) = 0?
    12x^2 - 4\sqrt{x} = 0

    Divide by 4 for the heck of it

    3x^2 = \sqrt{x}

    Square the answer:

    9x^4 = x

    x(9x^3-1) = 0

    I'm sure you can solve from there :]

    Remember though, because of the square root in the original equation x \geq 0
    Last edited by mr fantastic; September 11th 2009 at 05:28 AM. Reason: Edited quote.
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