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Thread: What is x in 12x^2 - (4/squarerootx) = 0?

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    What is x in 12x^2 - (4/squarerootx) = 0?

    What is x in 12x^2 - (4/squarerootx) = 0?
    Last edited by mr fantastic; Sep 11th 2009 at 05:27 AM. Reason: Copied question from post title into main body of post
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    Quote Originally Posted by marie7 View Post
    What is x in 12x^2 - (4/squarerootx) = 0?
    $\displaystyle 12x^2 - 4\sqrt{x} = 0$

    Divide by 4 for the heck of it

    $\displaystyle 3x^2 = \sqrt{x}$

    Square the answer:

    $\displaystyle 9x^4 = x$

    $\displaystyle x(9x^3-1) = 0$

    I'm sure you can solve from there :]

    Remember though, because of the square root in the original equation $\displaystyle x \geq 0$
    Last edited by mr fantastic; Sep 11th 2009 at 05:28 AM. Reason: Edited quote.
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