What is x in 12x^2 - (4/squarerootx) = 0?

Last edited by mr fantastic; Sep 11th 2009 at 06:27 AM. Reason: Copied question from post title into main body of post

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Originally Posted by marie7 What is x in 12x^2 - (4/squarerootx) = 0? Divide by 4 for the heck of it Square the answer: I'm sure you can solve from there :] Remember though, because of the square root in the original equation

Last edited by mr fantastic; Sep 11th 2009 at 06:28 AM. Reason: Edited quote.

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