What is x in 12x^2 - (4/squarerootx) = 0?

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- Sep 10th 2009, 01:02 PM #1

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- Jul 2009
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- Sep 10th 2009, 01:21 PM #2
$\displaystyle 12x^2 - 4\sqrt{x} = 0$

Divide by 4 for the heck of it

$\displaystyle 3x^2 = \sqrt{x}$

Square the answer:

$\displaystyle 9x^4 = x$

$\displaystyle x(9x^3-1) = 0$

I'm sure you can solve from there :]

Remember though, because of the square root in the original equation $\displaystyle x \geq 0$