Results 1 to 2 of 2

Math Help - What is x in 12x^2 - (4/squarerootx) = 0?

  1. #1
    Junior Member
    Joined
    Jul 2009
    Posts
    47

    What is x in 12x^2 - (4/squarerootx) = 0?

    What is x in 12x^2 - (4/squarerootx) = 0?
    Last edited by mr fantastic; September 11th 2009 at 06:27 AM. Reason: Copied question from post title into main body of post
    Follow Math Help Forum on Facebook and Google+

  2. #2
    -1
    e^(i*pi)'s Avatar
    Joined
    Feb 2009
    From
    West Midlands, England
    Posts
    3,053
    Thanks
    1
    Quote Originally Posted by marie7 View Post
    What is x in 12x^2 - (4/squarerootx) = 0?
    12x^2 - 4\sqrt{x} = 0

    Divide by 4 for the heck of it

    3x^2 = \sqrt{x}

    Square the answer:

    9x^4 = x

    x(9x^3-1) = 0

    I'm sure you can solve from there :]

    Remember though, because of the square root in the original equation x \geq 0
    Last edited by mr fantastic; September 11th 2009 at 06:28 AM. Reason: Edited quote.
    Follow Math Help Forum on Facebook and Google+

Search Tags


/mathhelpforum @mathhelpforum