Printable View

What is x in 12x^2 - (4/squarerootx) = 0?

Quote: Originally Posted by marie7 What is x in 12x^2 - (4/squarerootx) = 0? Divide by 4 for the heck of it Square the answer: I'm sure you can solve from there :] Remember though, because of the square root in the original equation