I have a question which is apparently worth 4 marks (of 10!) which states that there is a possible 4 answers for the following:

Solve $\displaystyle |x|(x-1)=2$ to which I simply worked out by expanding the LHS to $\displaystyle 2x-x=2$ and thus $\displaystyle x=2$

I have no idea what other way I can look at this, so what am I missing?