What number must be added to both the numerator and denominator of 3/4 in order to finish with 1/3? I've been flipping out over this for a while now, I have a feeling that I'm overcomplicating it...
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Originally Posted by Biscuithead What number must be added to both the numerator and denominator of 3/4 in order to finish with 1/3? I've been flipping out over this for a while now, I have a feeling that I'm overcomplicating it... $\displaystyle \frac{3+n}{4+n} = \frac{1}{3}$ $\displaystyle 9+3n = 4+n$ $\displaystyle 2n = -5$ $\displaystyle n = -\frac{5}{2}$
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