# solving for X

• Sep 9th 2009, 01:39 AM
realistic
solving for X
http://img33.imageshack.us/img33/1213/70815989.jpgcan someone help with next step? plz(Bow)
• Sep 9th 2009, 02:13 AM
Researcher
Quote:

Originally Posted by realistic
http://img33.imageshack.us/img33/1213/70815989.jpgcan someone help with next step? plz(Bow)

y=p/(k-x)
• Sep 9th 2009, 02:20 AM
realistic
back of book has a different answer :(
• Sep 9th 2009, 03:21 AM
Hello realistic
Quote:

Originally Posted by realistic
http://img33.imageshack.us/img33/1213/70815989.jpgcan someone help with next step? plz(Bow)

$\displaystyle x = k - \frac{\sqrt{pz}}{y}$

$\displaystyle \Rightarrow x-k=-\frac{\sqrt{pz}}{y}$

$\displaystyle \Rightarrow k-x=\frac{\sqrt{pz}}{y}$

$\displaystyle \Rightarrow (k-x)y=\sqrt{pz}$

$\displaystyle \Rightarrow y = \frac{\sqrt{pz}}{k-x}$

• Sep 9th 2009, 03:26 AM
realistic
Quote:

Hello realistic$\displaystyle x = k - \frac{\sqrt{pz}}{y}$

$\displaystyle \Rightarrow x-k=-\frac{\sqrt{pz}}{y}$

$\displaystyle \Rightarrow k-x=\frac{\sqrt{pz}}{y}$

$\displaystyle \Rightarrow (k-x)y=\sqrt{pz}$

$\displaystyle \Rightarrow y = \frac{\sqrt{pz}}{k-x}$

Multiply both sides by $\displaystyle -1$, noting that $\displaystyle -(x-k) = k-x$.