simplify

• Sep 9th 2009, 12:44 AM
realistic
simplify
need help on a step by step approach to doing these and similar

http://img179.imageshack.us/img179/548/sum.jpgi can do the basic ones but when they add fractions etc i get lost
• Sep 9th 2009, 12:48 AM
Quote:

Originally Posted by realistic
need help on a step by step approach to doing these and similar

http://img179.imageshack.us/img179/548/sum.jpgi can do the basic ones but when they add fractions etc i get lost

Hi

i Hope u mean

$\displaystyle \frac{48a^4y^{-5}}{\frac{1}{8}y^{-3}a^{\frac{1}{2}}}$

$\displaystyle (48\times8)a^4a^{-\frac{1}{2}}y^{-5}y^3$

Then use the law of indices to continue ..
• Sep 9th 2009, 01:07 AM
realistic
Quote:

Hi

i Hope u mean

$\displaystyle \frac{48a^4y^{-5}}{\frac{1}{8}y^{-3}a^{\frac{1}{2}}}$

$\displaystyle (48\times8)a^4a^{-\frac{1}{2}}y^{-5}y^3$

Then use the law of indices to continue ..

yeah i got the indices laws down but could you explain how you got times 8 plz silly question but need to clarify
• Sep 9th 2009, 04:49 AM
$\displaystyle \frac{48}{\frac{1}{8}}=48\times\frac{8}{1}$