simplify

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September 9th 2009, 12:44 AM
realistic

simplify

need help on a step by step approach to doing these and similar

http://img179.imageshack.us/img179/548/sum.jpgi can do the basic ones but when they add fractions etc i get lost
September 9th 2009, 12:48 AM
mathaddict

Quote:

Originally Posted by realistic

need help on a step by step approach to doing these and similar

http://img179.imageshack.us/img179/548/sum.jpgi can do the basic ones but when they add fractions etc i get lost

Hi

i Hope u mean

$\frac{48a^4y^{-5}}{\frac{1}{8}y^{-3}a^{\frac{1}{2}}}$

$(48\times8)a^4a^{-\frac{1}{2}}y^{-5}y^3$

Then use the law of indices to continue ..
September 9th 2009, 01:07 AM
realistic

Quote:

Originally Posted by mathaddict

Hi

i Hope u mean

$\frac{48a^4y^{-5}}{\frac{1}{8}y^{-3}a^{\frac{1}{2}}}$

$(48\times8)a^4a^{-\frac{1}{2}}y^{-5}y^3$

Then use the law of indices to continue ..

yeah i got the indices laws down but could you explain how you got times 8 plz silly question but need to clarify
September 9th 2009, 04:49 AM
mathaddict

Quote:

Originally Posted by realistic

yeah i got the indices laws down but could you explain how you got times 8 plz silly question but need to clarify

$<br /> \frac{48}{\frac{1}{8}}=48\times\frac{8}{1} <br />$

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