# One to One functions

• Sep 8th 2009, 07:16 PM
Chinnie15
One to One functions
If f and g are one-to-one functions where f(-7)=6, F(2)=9 and g(-7)=9, then find-

a)g of f^-1(6)

b)f of g^-1(9)

c)f^-1 of g(-7)

I'm confused as to what goes where? I know how to compose functions, but this is confusing to me?
• Sep 8th 2009, 07:25 PM
Prove It
Quote:

Originally Posted by Chinnie15
If f and g are one-to-one functions where f(-7)=6, F(2)=9 and g(-7)=9, then find-

a)g of f^-1(6)

b)f of g^-1(9)

c)f^-1 of g(-7)

I'm confused as to what goes where? I know how to compose functions, but this is confusing to me?

Remember that when you have inverse functions, the $x$ and $y$ values swap.

So if $f(-7) = 6$ then $f^{-1}(6) = -7$.

If $F(2) = 9$ then $F^{-1}(9) = 2$.

If $g(-7) = 9$ then $g^{-1}(9) = -7$.

a) $g\left(f^{-1}(6)\right) = g(-7) = 9$.
b) $f\left(g^{-1}(9)\right) = f(-7) = 6$.
c) $f^{-1}\left(g(-7)\right) = f^{-1}(9)$.
Since we do not have any information about $f^{-1}(9)$ we can not go any further.