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Math Help - Am I correct with these problems?

  1. #1
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    Am I correct with these problems?

    1, (-4)3

    (-4).(-4). (-4).(-4)


    2, -52

    -5 . -5


    3, (2/3)2

    (2/3) . (2/3)


    4,
    (2/3)2

    (2/3) . (2/3)


    5,
    (-3)4

    (-3) . (-3) . (-3) . (-3)



    So do my answers to this questions seem correct?

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  2. #2
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    No, Yes, Yes, Yes & Yes

     <br />
(-4)^3 = -4\times -4\times -4<br />
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  3. #3
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    Quote Originally Posted by pickslides View Post
    No, Yes, Yes, Yes & Yes

     <br />
(-4)^3 = -4\times -4\times -4<br />
    Ok,

    How do I solve questions 3 and 4?

    Thank you!
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  4. #4
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    Quote Originally Posted by Kevin19 View Post
    Ok,

    How do I solve questions 3 and 4?

    Thank you!
    First, you won't be "solving". To "solve" means to find the value of a pronumeral.

    You will be "simplifying".


    Anyway...

    1. (-4)^3 = (-4)\cdot(-4)\cdot(-4)

     = -64.


    2. (-5)^2 = (-5)\cdot(-5)

     = 25


    3. \left(\frac{2}{3}\right)^2 = \frac{2^2}{3^2}

     = \frac{4}{9}


    4. It appears that Q. 4 is the same as Q. 3.


    5. (-3)^4 = (-3)\cdot(-3)\cdot(-3)\cdot(-3)

     = 81.
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  5. #5
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    They are the same question

     <br />
\left(\frac{2}{3}\right)^2 = \frac{2}{3} \times \frac{2}{3} = \frac{2\times 2 }{3 \times 3} = \frac{4}{9}<br />
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