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Math Help - Population Density help

  1. #1
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    Population Density help

    I am trying to find the population density per acre in a given area of land.

    1 acre = 43,560 ft

    Area 01 has 4188197649.77891 ft & 76117 people
    \frac{4188197649.77891}{43,560}= 96,147.8 acres

    Now that I have the total amount of acres within Area 01, could I take that total divided by the number of people in it?
    e.g.

    \frac{76117 people}{96,147.8 acres} about .79 people per an acre? This doesnt seem correct at all.

    Many thanks for any help
    Last edited by allyourbass2212; September 8th 2009 at 10:05 AM.
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  2. #2
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    Thanks Masters

    Just to be safe then

     <br />
\frac{96,147.8 acres}{76117 people}= 1.26 people per an acre

    1.26 people per acre x 76117 people = the original amount of acres that we started with about 97k

    Does this look good? And how come population density is the inverse of this? e.g. \frac{population 1000}{area 1000 square miles} =1 person per square mile
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  3. #3
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    Quote Originally Posted by allyourbass2212 View Post
    Thanks Masters

    Just to be safe then

     <br />
\frac{96,147.8 acres}{76117 people}= 1.26 people per an acre

    1.26 people per acre x 76117 people = the original amount of acres that we started with about 97k

    Does this look good? And how come population density is the inverse of this? e.g. \frac{population 1000}{area 1000 square miles} =1 person per square mile
    You are correct in your reasoning. The fact that I mentioned that there are 1.26 people per acre is irrelavent.

    Pop. density is found by dividing the population by the area as you did. If you have 1000 sq. miles for 1000 people, that would be a density of 1 person per square mile.
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