# Population Density help

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• Sep 8th 2009, 10:32 AM
allyourbass2212
Population Density help
I am trying to find the population density per acre in a given area of land.

1 acre = 43,560 ft

Area 01 has 4188197649.77891 ft & 76117 people
$\frac{4188197649.77891}{43,560}= 96,147.8$ acres

Now that I have the total amount of acres within Area 01, could I take that total divided by the number of people in it?
e.g.

$\frac{76117 people}{96,147.8 acres}$ about .79 people per an acre? This doesnt seem correct at all.

Many thanks for any help
• Sep 8th 2009, 11:03 AM
allyourbass2212
Thanks Masters

Just to be safe then

$
\frac{96,147.8 acres}{76117 people}= 1.26$
people per an acre

1.26 people per acre x 76117 people = the original amount of acres that we started with about 97k

Does this look good? And how come population density is the inverse of this? e.g. $\frac{population 1000}{area 1000 square miles}$ =1 person per square mile
• Sep 8th 2009, 11:09 AM
masters
Quote:

Originally Posted by allyourbass2212
Thanks Masters

Just to be safe then

$
\frac{96,147.8 acres}{76117 people}= 1.26$
people per an acre

1.26 people per acre x 76117 people = the original amount of acres that we started with about 97k

Does this look good? And how come population density is the inverse of this? e.g. $\frac{population 1000}{area 1000 square miles}$ =1 person per square mile

You are correct in your reasoning. The fact that I mentioned that there are 1.26 people per acre is irrelavent.

Pop. density is found by dividing the population by the area as you did. If you have 1000 sq. miles for 1000 people, that would be a density of 1 person per square mile.