# Math Help - Any chance of solving for theta2

1. ## Any chance of solving for theta2

Any chance of solving for $\theta_2$ in either cartesian or polar form?

$\ \cos\theta_1=\sqrt{\frac{(\pi+2\theta_2(b-1))^2}{\pi^2 (1+\tan^2{\theta_2})}}$

Thanks

2. Originally Posted by rainer
Any chance of solving for $\theta_2$ in either cartesian or polar form?

$\ \cos\theta_1=\sqrt{\frac{(\pi+2\theta_2(b-1))^2}{\pi^2 (1+\tan^2{\theta_2})}}$

Thanks
Hi

$1+\tan^2{\theta_2} = \frac{1}{\cos^2{\theta_2}}$

$\pi\ \cos\theta_1=|(\pi+2\theta_2(b-1))\cos{\theta_2}|$

Unless you have additional information on $\theta_2$ you cannot solve without calculator