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Math Help - Any chance of solving for theta2

  1. #1
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    Any chance of solving for theta2

    Any chance of solving for \theta_2 in either cartesian or polar form?

    \ \cos\theta_1=\sqrt{\frac{(\pi+2\theta_2(b-1))^2}{\pi^2 (1+\tan^2{\theta_2})}}


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  2. #2
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    Quote Originally Posted by rainer View Post
    Any chance of solving for \theta_2 in either cartesian or polar form?

    \ \cos\theta_1=\sqrt{\frac{(\pi+2\theta_2(b-1))^2}{\pi^2 (1+\tan^2{\theta_2})}}


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    Hi

    1+\tan^2{\theta_2} = \frac{1}{\cos^2{\theta_2}}

    \pi\ \cos\theta_1=|(\pi+2\theta_2(b-1))\cos{\theta_2}|

    Unless you have additional information on \theta_2 you cannot solve without calculator
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