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Thread: Factoring Completely

  1. September 7th 2009, 04:09 PM #1
    absvalue
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    Factoring Completely

    Is this expression factored completely?

    (2a^{2} - ab)(4a^{4} + 2a^{3}b + a^{2}b^{2})
    Last edited by absvalue; September 7th 2009 at 04:19 PM.
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  2. September 7th 2009, 04:33 PM #2
    skeeter
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    Quote Originally Posted by absvalue View Post
    Is this expression factored completely?

    (2a^{2} - ab)(4a^{4} + 2a^{3}b + a^{2}b^{2})
    not quite, those terms in ( ... ) still have common factor(s)

    a(2a-b) \cdot a^2(4a^2 + 2ab + b^2)

    finish ...
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  3. September 7th 2009, 04:35 PM #3
    absvalue
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    Thanks. So the expression wasn't factored completely because the common factor a was in the first term, and the common factor a^{2} was in the second?
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