Factoring Completely

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September 7th 2009, 04:09 PM
absvalue

Factoring Completely

Is this expression factored completely?

$(2a^{2} - ab)(4a^{4} + 2a^{3}b + a^{2}b^{2})$
September 7th 2009, 04:33 PM
skeeter

Quote:

Originally Posted by absvalue

Is this expression factored completely?

$(2a^{2} - ab)(4a^{4} + 2a^{3}b + a^{2}b^{2})$

not quite, those terms in ( ... ) still have common factor(s)

$a(2a-b) \cdot a^2(4a^2 + 2ab + b^2)$

finish ...
September 7th 2009, 04:35 PM
absvalue

Thanks. So the expression wasn't factored completely because the common factor $a$ was in the first term, and the common factor $a^{2}$ was in the second?

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