# Factoring Completely

• Sep 7th 2009, 05:09 PM
absvalue
Factoring Completely
Is this expression factored completely?

$(2a^{2} - ab)(4a^{4} + 2a^{3}b + a^{2}b^{2})$
• Sep 7th 2009, 05:33 PM
skeeter
Quote:

Originally Posted by absvalue
Is this expression factored completely?

$(2a^{2} - ab)(4a^{4} + 2a^{3}b + a^{2}b^{2})$

not quite, those terms in ( ... ) still have common factor(s)

$a(2a-b) \cdot a^2(4a^2 + 2ab + b^2)$

finish ...
• Sep 7th 2009, 05:35 PM
absvalue
Thanks. So the expression wasn't factored completely because the common factor $a$ was in the first term, and the common factor $a^{2}$ was in the second?