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Math Help - Exponent laws,rationalization and interval notation

  1. #1
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    Exponent laws,rationalization and interval notation

    The expression
    equals
    where r, the exponent of h, is: ?
    and t, the exponent of s, is: ?
    and k, the leading coefficient is: 2

    If you rationalize the denominator of
    then you will get
    where , , and are all positive integers (with no common factors).

    7
    4
    ?

    Solve the following inequality. Write the answer in interval notation.
    Note: If the answer includes more than one interval write the intervals separated by the "union" symbol, U. If needed enter as infinity and as -infinity .

    4< 3x+1 <6
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  2. #2
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    Quote Originally Posted by wannous View Post
    The expression
    equals
    where r, the exponent of h, is: ?
    and t, the exponent of s, is: ?
    and k, the leading coefficient is: 2

    If you rationalize the denominator of
    then you will get
    where , , and are all positive integers (with no common factors).

    7
    4
    ?

    Solve the following inequality. Write the answer in interval notation.
    Note: If the answer includes more than one interval write the intervals separated by the "union" symbol, U. If needed enter as infinity and as -infinity .

    4< 3x+1 <6
    \frac{\sqrt[4]{16h^{-9}s^{-5}}}{\sqrt[4]{h^{-8}s^3}} = \sqrt[4]{\frac{16h^{-9}s^{-5}}{h^{-8}s^3}} = \sqrt[4]{16h^{-1}s^{-8}} = (16h^{-1}s^{-8})^{\frac{1}{4}} = ?



    \frac{1}{7\sqrt{5}-4\sqrt{3}} \cdot \frac{7\sqrt{5}+4\sqrt{3}}{7\sqrt{5}+4\sqrt{3}} = ?



    4< 3x+1 < 6

    subtract 1 from all terms ...

    3 < 3x < 5

    last step is to divide all terms by 3 ...
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  3. #3
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    thank you very much
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