| 3x^2+5x-4 | = 2x-1 and this one | 7x +5 | - 2x >= 11
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Originally Posted by loliki | 3x^2+5x-4 | = 2x-1 and this one | 7x +5 | - 2x >= 11 Hi For the first one There will be 2 cases : $\displaystyle 3x^2+5x-4=2x-1$ OR $\displaystyle -3x^2-5x+4=2x-1$ For the second one There will also be 2 cases $\displaystyle 7x+5-2x\geq11$ OR $\displaystyle -7x-5-2x\geq11$
Thx dude, but.. i know about the 2 cases, i don't know what should i do after the cases, how can i solve the inequalities ?
Originally Posted by loliki Thx dude, but.. i know about the 2 cases, i don't know what should i do after the cases, how can i solve the inequalities ? $\displaystyle 7x + 5 \ge 2x + 11$ $\displaystyle 5x \ge 6$ $\displaystyle x \ge \frac{6}{5}$ $\displaystyle -(7x + 5) \ge 2x+11$ $\displaystyle -7x-5 \ge 2x+11$ $\displaystyle -9x \ge 16$ $\displaystyle x \le -\frac{16}{9}$
Thank you a lot!!!
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