hi, i've got and i've got it down to if i move the -40k across i get and the answer is

but if i move the 109 across and make it i get shouldn't it be the same whicever way i do it? what am i doing wrong?

thanks

Mark

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- Sep 7th 2009, 04:18 AMmarkinequality distinct real roots
hi, i've got and i've got it down to if i move the -40k across i get and the answer is

but if i move the 109 across and make it i get shouldn't it be the same whicever way i do it? what am i doing wrong?

thanks

Mark - Sep 7th 2009, 04:30 AMmr fantastic
It would help if you posted the question rather than diving into what you've done and leaving us all to guess.

I assume the question asks you to find the set of values of k for which has real solutions.

which is consistent with the first answer.

Your mistake was not reversing the inequality sign when multiplying or dividing by a negative number. - Sep 7th 2009, 04:37 AMmark
ahhh, i didn't know you had to do that. yeah sorry about lack of info. so its reversed if there's a negative number involved in division or multiplication. are there any exceptions? like double negatives? i suppose its unlikely that a double negative division would be an exception because that actually was the case in the question i just posted