(z-3)(z^2 + 25) (z-3)((z + 5)^2 - 10z) (z-3)(z + 5 + i)(z + 5 - i) Does it make sense?
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how did you get the third line from the second? $\displaystyle (z-3)(z^2+25) = (z-3)(z+5i)(z-5i)$ looks better
Originally Posted by Taluivren how did you get the third line from the second? $\displaystyle (z-3)(z^2+25) = (z-3)(z+5i)(z-5i)$ looks better I'm not sure, that's why I was wondering. I thought that if I subtracted 10 it would even out the equation and I could leave it as a complex number, but after re-working it I found your way much more helpful (and correct ).
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