Thread: algebra 2 question

well this problem seems pretty long. can someone show me this step by step?

If f(x)= -4x²+2x-3, evaluate:

f(y+1) and 2f(5)

the first thing i did was get these:

-4(y+1)²+2(y+1)-3=??

2[-4(5)²+2(5)-3]=??

if i did something wrong, please tell me. and if not i would like to see how it is done. thanks.

Originally Posted by nike23

well this problem seems pretty long. can someone show me this step by step?

If f(x)= -4x²+2x-3, evaluate:

f(y+1) and 2f(5)

the first thing i did was get these:

-4(y+1)²+2(y+1)-3=??

2[-4(5)²+2(5)-3]=??

if i did something wrong, please tell me. and if not i would like to see how it is done. thanks.

They're both set up properly. Now simplify them!

What answer have you got?
Varify the same. all the best.

Originally Posted by nike23

well this problem seems pretty long. can someone show me this step by step?

If f(x)= -4x²+2x-3, evaluate:

f(y+1) and 2f(5)

the first thing i did was get these:

-4(y+1)²+2(y+1)-3=??

2[-4(5)²+2(5)-3]=??

if i did something wrong, please tell me. and if not i would like to see how it is done. thanks.

for the 2[-4(5)²+2(5)-3], i came up with -186.
and the first one, im not sure how i should evaluate it. the last thing i put was:
-4y²+6y+5, how much further should i go?

Originally Posted by nike23

for the 2[-4(5)²+2(5)-3], i came up with -186.

and the first one, im not sure how i should evaluate it. the last thing i put was:
-4y²+6y+5, how much further should i go?

I get ...