solve the following quadratic:

4x^2+17x=6x-2x^2

looks easy enough, but apparently there's a square root in the answer, which scares my baby brain.

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- Oct 1st 2005, 11:26 AMx-disturbed-xbaby brain can't cut the mustard
solve the following quadratic:

4x^2+17x=6x-2x^2

looks easy enough, but apparently there's a square root in the answer, which scares my baby brain. - Oct 4th 2005, 12:56 PMhemza
Hi,

4x^2+17x=6x-2x^2.

**When you have x^2 and x in the same equality put always everything =0.**

Why not isolate x from the beggining, well because we have different powers of x and which one do we isolate... Beep! can't do.

So, we use the trick putting everything=0. So we transfer the 6x (which is positive it gets negative on the other side and the opposite goes with the -2x^2). We get : 4x^2+17x-6x+2x^2=0 (nothing left on the right).

We add the x^2 together and the x together and get 6x^2+11x=0 so we take out an x and get x(6x+11)=0 so to get 0 we must have either x=0 or (6x+11)=0. So if x=0 well, x=0. And if 6x+11=0 so x=-11/6. So two possible answer: 0 or -11/6. No square roots needed.

Try them in 4x^2+17x=6x-2x^2 and you'll get an equality (either all x=0 or all x = -11/6 not at the same time) !!! - Oct 4th 2005, 02:04 PMx-disturbed-x
Thank you! :) I owe you one