evaluate stuck at last bit

**realistic** · September 4th 2009, 06:33 PM

if someone could please explain to me if im doing this wrong or what morei have to do to make it right

**skeeter** · September 4th 2009, 06:35 PM

$-3 - \sqrt{1} = -3 - 1 = -4$

**realistic** · September 4th 2009, 06:38 PM

Originally Posted by skeeter

$-3 - \sqrt{1} = -3 - 1 = -4$

the answer in the back says

3 - root 1

= 2

**skeeter** · September 4th 2009, 06:45 PM

Originally Posted by realistic

the answer in the back says

3 - root 1

= 2

sorry ... I just noted your last step.

$-b - \sqrt{b^2-4ac}$

$-(-3) - \sqrt{1} = 3 - 1 = 2$

**realistic** · September 4th 2009, 06:49 PM

Originally Posted by skeeter

sorry ... I just noted your last step.

$-b - \sqrt{b^2-4ac}$

$-(-3) - \sqrt{1} = 3 - 1 = 2$

ah i see what i did wrong forgot that extra negative thanks for clearing that up for me

**pacman** · September 4th 2009, 08:53 PM

life is like that . . . . simple mistake that stucks us up.

Thread: evaluate stuck at last bit