evaluate stuck at last bit

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September 4th 2009, 06:33 PM
realistic

evaluate stuck at last bit

http://img196.imageshack.us/img196/1524/mathsn.jpg
if someone could please explain to me if im doing this wrong or what morei have to do to make it right (Bow)
September 4th 2009, 06:35 PM
skeeter

$-3 - \sqrt{1} = -3 - 1 = -4$
September 4th 2009, 06:38 PM
realistic

Quote:

Originally Posted by skeeter

$-3 - \sqrt{1} = -3 - 1 = -4$

the answer in the back says

3 - root 1

= 2
September 4th 2009, 06:45 PM
skeeter

Quote:

Originally Posted by realistic

the answer in the back says

3 - root 1

= 2

sorry ... I just noted your last step.

$-b - \sqrt{b^2-4ac}$

$-(-3) - \sqrt{1} = 3 - 1 = 2$
September 4th 2009, 06:49 PM
realistic

Quote:

Originally Posted by skeeter

sorry ... I just noted your last step.

$-b - \sqrt{b^2-4ac}$

$-(-3) - \sqrt{1} = 3 - 1 = 2$

ah i see what i did wrong forgot that extra negative thanks for clearing that up for me (Bow)
September 4th 2009, 08:53 PM
pacman

life is like that . . . . simple mistake that stucks us up.

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