# evaluate stuck at last bit

• Sep 4th 2009, 06:33 PM
realistic
evaluate stuck at last bit
http://img196.imageshack.us/img196/1524/mathsn.jpg
if someone could please explain to me if im doing this wrong or what morei have to do to make it right (Bow)
• Sep 4th 2009, 06:35 PM
skeeter
$-3 - \sqrt{1} = -3 - 1 = -4$
• Sep 4th 2009, 06:38 PM
realistic
Quote:

Originally Posted by skeeter
$-3 - \sqrt{1} = -3 - 1 = -4$

the answer in the back says

3 - root 1

= 2
• Sep 4th 2009, 06:45 PM
skeeter
Quote:

Originally Posted by realistic
the answer in the back says

3 - root 1

= 2

sorry ... I just noted your last step.

$-b - \sqrt{b^2-4ac}$

$-(-3) - \sqrt{1} = 3 - 1 = 2$
• Sep 4th 2009, 06:49 PM
realistic
Quote:

Originally Posted by skeeter
sorry ... I just noted your last step.

$-b - \sqrt{b^2-4ac}$

$-(-3) - \sqrt{1} = 3 - 1 = 2$

ah i see what i did wrong forgot that extra negative thanks for clearing that up for me (Bow)
• Sep 4th 2009, 08:53 PM
pacman
life is like that . . . . simple mistake that stucks us up.