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Math Help - I need help on factoring these.

  1. #1
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    I need help on factoring these.

    By factoring using the zero product principal.
    x + 1 = 9^3 + 9^2

    9y^3+8=4y+18y^2

    4x^3 - 12x^2 = 9x -27

    Eeeep. I hate Algebra. ;c
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  2. #2
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    Quote Originally Posted by Maditay View Post
    9y^3+8=4y+18y^2
    A hint on this one:
    9y^3 - 4y - 18y^2 + 8 = 0
    y(9y^2 - 4) - 2(9y^2 - 4) = 0

    Did you follow that? Can you finish it?

    If not, almost impossible to classroom-teach here.
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  3. #3
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    Quote Originally Posted by Maditay View Post
    By factoring using the zero product principal.
    x + 1 = 9^3 + 9^2

    9y^3+8=4y+18y^2

    4x^3 - 12x^2 = 9x -27

    Eeeep. I hate Algebra. ;c

    here is link which may help you
    Factor theorem - Wikipedia, the free encyclopedia
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  4. #4
    A riddle wrapped in an enigma
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    Quote Originally Posted by Maditay View Post
    By factoring using the zero product principal.
    x + 1 = 9^3 + 9^2

    9y^3+8=4y+18y^2

    4x^3 - 12x^2 = 9x -27

    Eeeep. I hate Algebra. ;c
    Hi Maditay,

    That first one doesn't make a lot of sense. Turns out to be x = 809. What's to factor? It's linear.

    The last one can be grouped to factor. Bring everything to the left side and set equal to zero.

    4x^3-12x-9x+27=0

    4x^2(x-3)-9(x-3)=0

    Finish up by factoring out the common factor of (x - 3), and then use your zero product property.
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