I still dont understand
In February 2007 the Ken-Ton school distict canceles classes due to severe windchill on a couple of different days. Sustained windchill readings of -40 degrees Fareinheit or below regarded as dangerous due to the risk of severe frostbite. The air temperature in the early morning was around -15 degrees farenheit on the mornings when Ken-Ton canceled school. How bad was the wind blowing on those mornings?
(The windchill model is from Bosch & Cobb, UMAP Module No. 658, "WindChill")
Is the answer 35 degrees or am I thinking to simple. My professor enjoys decieving us so Im not sure where to start with this question
The answer can't be "35 degrees" because you are not asked for temperature! You are asked for windspeed.
Originally Posted by asweet1
What is the formula from the "Windchill" module cited? Presumably, it has variables for "temperature", "wind speed" and "windchill". Set windchill equal to -40, temperature equal to -15, in that formula and solve for windspeed.
so would the answer be 35 mph the formula i came up is 40=15-w (w is windspeed)
Your formula can't be correct because the units aren't even compatible
what is degrees - miles per hour?
See the New wind chill index formula in the link below
Wind chill - Wikipedia, the free encyclopedia
It might thave been better to do a little classic research instead of just
throwing numbers around and hoping it is correct.
All you have to do is a search for Wind Chill Index