Originally Posted by

**sleels** Hello, I need some help with this problem.

The problem is:

$\displaystyle Ln(x) + Ln(x-1) = 1 $

Heres what I got

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$\displaystyle Ln(x) + Ln(x-1) = 1]$

$\displaystyle Ln(x^2 - x) = 1$

$\displaystyle x^2 - x = e^1$

$\displaystyle x^2 - x - e = 0$

Now I use the quadratic equation to get

$\displaystyle \frac{x \pm \sqrt{x^2 - 4(x^2)(-e)}}{2x^2}$

The answer is supposed to be :

$\displaystyle

\frac{(1 \pm \sqrt{1 + 4e})}{2}$

I'm having some difficulty seeing how they got that answer.

Did I do something incorrectly? Or am I simplifying wrong?

Thank you