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Thread: exponent rules help

  1. September 2nd 2009, 01:04 PM #1
    lbj2322
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    exponent rules help

    simplify b^(y-1)b^(1-y)
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  2. September 2nd 2009, 01:37 PM #2
    Plato
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    Quote Originally Posted by lbj2322 View Post
    simplify b^(y-1)b^(1-y)
    Assume that b\ne 0.
    b^{y-1}b^{1-y}=b^{(y-1)+(1-y)}=b^0=1
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